Question
\(If \log_{x}\left(\frac{9}{16}\right)= -\frac{1}{2}\) , then x is equal to:
Answer: Option D
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\( \log_{x}\left(\frac{9}{16}\right)= -\frac{1}{2}\)
= \( x^{\frac{1}{2}}=\frac{9}{16}\)
= \( \frac{1}{x}=\frac{9}{16}\)
= \( x= \frac{16}{9}\)
= \( x=\left(\frac{16}{9}\right)^{2}\)
= \( x=\frac{256}{81}\)
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