If in a ΔABC, cosAa=cosBb=cosCc, then what can be said about the triangle?

Options:

A . Isoceles triangle

B . Right angled triangle

C . Equilateral triangle

D . Acute triangle

E . 1

Answer: Option C : C Since rule says that = asinA=bsinB=csinC=k Therefore,a=k(sinA), b=k(sinB) and c=k(sinC) We can write cosAa=cosBb=cosCc as cosAksinA=cosBksinB=cosCksinC =cot A=cot B=cot C ⇒ A=B=C(Equilateral Triangle).

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