Question
If in a coil rate of change of area is 5metre2millisecond and current become 1 amp form 2 amp in 2× 10−3 sec. If magnetic field is 1 Tesla then self inductance of the coil is
Answer: Option D
:
D
e=B.dAdt=Ldidt⇒1×510−3=L×(2−1)2×10−3⇒L=10H
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:
D
e=B.dAdt=Ldidt⇒1×510−3=L×(2−1)2×10−3⇒L=10H
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