A hundred turns of insulated copper wire are wrapped around an iron cylinder of

Question

A hundred turns of insulated copper wire are wrapped around an iron cylinder of area

10^{- 3} m^{2}

and are connected to a resistor. The total resistance in the circuit is 10 ohms. If the longitudinal magnetic induction in the iron changes from 1 weber

m^{- 2}

, in one direction to 1 Weber

m^{- 2}

in the opposite direction, how much charge flows through the circuit?

Options:

A . 2× 10−2C

B . 2× 10−3C

C . 2× 10−4C

D . 2× 10−5C

Answer: Option A
:
A

d Q = \frac{d ϕ}{R} = \frac{n A d B}{R} = \frac{100 \times 1 \times 10^{- 3} \times 2}{10} = 2 \times 10^{- 2} C

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