If $$\frac{{{\text{ }}{x^2} + 1}}{{{x^2}}} = 2{\text{,}}$$ then the value of $$\frac{{x - 1}}{x}$$ is? Options: A . &nbsp-2 B . &nbsp0 C . &nbsp1 D . &nbsp-1

If $$\frac{{{\text{ }}{x^2} + 1}}{{{x^2}}} = 2{\text{,}}$$ then the value of

Question

If $$\frac{{{\text{ }}{x^2} + 1}}{{{x^2}}} = 2{\text{,}}$$ then the value of $$\frac{{x - 1}}{x}$$ is?

Options:

A . -2

B . 0

C . 1

D . -1

Answer: Option B

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