Question
If $$\frac{{2{{\tan }^2}{{30}^ \circ }}}{{1 - {{\tan }^2}{{30}^ \circ }}}$$ + $${\sec ^2}{45^ \circ }$$ - $${\sec ^2}{0^ \circ }$$ = $$x\sec {60^ \circ }{\text{,}}$$ then the value of x is?
Answer: Option B
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