The numerical value of 1 + $$\frac{1}{{{\text{co}}{{\text{t}}^2}{{63}^ \circ }}}

Question

The numerical value of 1 + $$\frac{1}{{{\text{co}}{{\text{t}}^2}{{63}^ \circ }}}$$ - $${\text{se}}{{\text{c}}^2}{27^ \circ }$$ + $$\frac{1}{{{{\sin }^2}{{63}^ \circ }}}$$ - $${\text{cose}}{{\text{c}}^2}{27^ \circ }$$ is?

Options:

A . 1

B . 2

C . -1

D . 0

Answer: Option D

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