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Question
If f(x)=

1xx+12xx(x1)x(x+1)3x(x1)x(x1)(x2)x(x21)

, then f(200) is equal to 
Options:
A .  1
B .  0
C .  200
D .  -200
Answer: Option B
:
B
f(X)=x(x+1)
1112xx1x3x(x1)(x1)(x2)x(x1)
=x(x+1)(x1)
1112xx1x3xx2x

Applying C2C2C1 and C3C3C1 then
f(x)=x(x+1)(x1)
1002xx1x3x2x22x
=x2(x+1)2(x1)
1002x113x22
=0
f(200)=0


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