Question
If f(x)=∣∣
∣
∣∣1xx+12xx(x−1)x(x+1)3x(x−1)x(x−1)(x−2)x(x2−1)∣∣
∣
∣∣, then f(200) is equal to
∣
∣∣1xx+12xx(x−1)x(x+1)3x(x−1)x(x−1)(x−2)x(x2−1)∣∣
∣
∣∣, then f(200) is equal to
Answer: Option B
:
B
f(X)=x(x+1)∣∣
∣∣1112xx−1x3x(x−1)(x−1)(x−2)x(x−1)∣∣
∣∣=x(x+1)(x−1)∣∣
∣∣1112xx−1x3xx−2x∣∣
∣∣
Applying C2→C2−C1 and C3→C3−C1 then
f(x)=x(x+1)(x−1)∣∣
∣∣1002x−x−1−x3x−2x−2−2x∣∣
∣∣=x2(x+1)2(x−1)∣∣
∣∣1002x−1−13x−2−2∣∣
∣∣=0∴f(200)=0
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:
B
f(X)=x(x+1)∣∣
∣∣1112xx−1x3x(x−1)(x−1)(x−2)x(x−1)∣∣
∣∣=x(x+1)(x−1)∣∣
∣∣1112xx−1x3xx−2x∣∣
∣∣
Applying C2→C2−C1 and C3→C3−C1 then
f(x)=x(x+1)(x−1)∣∣
∣∣1002x−x−1−x3x−2x−2−2x∣∣
∣∣=x2(x+1)2(x−1)∣∣
∣∣1002x−1−13x−2−2∣∣
∣∣=0∴f(200)=0
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