Question
If (a + 3b)(3a + b) = 4h2, then the angle between the lines represented by ax2+2hxy+by2=0 is
Answer: Option C
:
C
θ=tan−1(2√h2−aba+b)=tan−1(√4h2−4aba+b)
= tan−1(√3a2+3b2+10ab−4aba+b)=60∘.
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:
C
θ=tan−1(2√h2−aba+b)=tan−1(√4h2−4aba+b)
= tan−1(√3a2+3b2+10ab−4aba+b)=60∘.
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