If 13.6 ev energy is required to ionise the hydrogen atom, then the energy requi

Question

If 13.6 ev energy is required to ionise the hydrogen atom, then the energy required to remove an electron from first exited state (n = 2) is

Options:

A . 10.2 eV

B . 0 eV

C . 3.4 eV

D . 6.8 eV

Answer: Option C
:
C

E_{2} = - \frac{13.6}{n^{2}} = - \frac{13.6}{2^{2}}

= - 3.4 e V

E = 3.4 e V

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