The energy of the ground electronic state of hydrogen atom is -13.6 eV. The ener

Question

The energy of the ground electronic state of hydrogen atom is -13.6 eV. The energy of the first excited stae will be :

Options:

A . – 52.4 eV

B . – 27.2 eV

C . – 68 eV

D . – 3.4 eV

Answer: Option D
:
D

E = - \frac{13.6}{n^{2}} n = 2

= - \frac{13.6}{n^{2}} = - 3.4 e V

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