Question
If 1, 2, 3 and 4 represent the areas of the four triangles (of a parallelogram) with different shades, then _______.
Answer: Option B
:
B
Consider the figure below:
In △DAOand△OCB
∠DAO=∠OCB(Alternate angles)∠ADO=∠CBO(Alternate angles)AD=CB(Opposite sides of parallelogram)Hence,ΔADO≅ΔCBO(AAS congruence)Similarly it can be proved thatArea(ΔDOC)=Area(Δ(BOA)
In △ABD, AO is the median.
A median divides a triangle into two equal parts.
Hence 1 = 4
Similarly 2 = 3
∴1=2=3=4
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:
B
Consider the figure below:
In △DAOand△OCB
∠DAO=∠OCB(Alternate angles)∠ADO=∠CBO(Alternate angles)AD=CB(Opposite sides of parallelogram)Hence,ΔADO≅ΔCBO(AAS congruence)Similarly it can be proved thatArea(ΔDOC)=Area(Δ(BOA)
In △ABD, AO is the median.
A median divides a triangle into two equal parts.
Hence 1 = 4
Similarly 2 = 3
∴1=2=3=4
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