In the adjoining figure, ΔQPR is right-angled at Q in which QR = 6 cm and PQ =

Question

In the adjoining figure,

Δ Q P R

is right-angled at Q in which QR = 6 cm and PQ = 7 cm. Find the area of

Δ Q S R

, given that PS is parallel to QR.

In The Adjoining Figure, ΔQPR Is Right-angled At Q In Which...

Options:

A . 21 cm2

B . 20 cm2

C . 10 cm2

D . 11 cm2

Answer: Option A
:
A

Area of right angled triangle PQR
=

\frac{1}{2}

x Base x Height
=

\frac{1}{2}

x QR x PQ
=

\frac{1}{2}

x 6 x 7

= 21 c m^{2}

Δ Q P R

and

Δ Q S R

lie on same base QR and are between same parallels hence, their areas are equal.
Area

Δ Q P R

= Area

Δ Q S R

∴ A r e a o f Δ Q S R = 21 c m^{2}

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