Hydrogen atom in its ground state is excited by radiation of wavelength 975 ∘ A . How many lines will be there in the emission spectrum Options: A . &nbsp2 B . &nbsp4 C . &nbsp6 D . &nbsp8

Answer: Option C : C Using 1 λ = R [ 1 n 2 1 − 1 n 2 2 ] ⇒ 1 975 × 10 − 10 = 1.097 × 10 7 ( 1 1 2 − 1 n 2 ) ⇒ n = 4 Now number of spectral lines N = n ( n − 1 ) 2 = 4 ( 4 − 1 ) 2 = 6

Hydrogen atom in its ground state is excited by radiation of wavelength 975

Question

Hydrogen atom in its ground state is excited by radiation of wavelength

975 \circ A

. How many lines will be there in
the emission spectrum

Options:

A . 2

B . 4

C . 6

D . 8

Answer: Option C
:
C
Using

\frac{1}{λ} = R [\frac{1}{n_{1}^{2}} - \frac{1}{n_{2}^{2}}] \Rightarrow \frac{1}{975 \times 10^{- 10}} = 1.097 \times 10^{7} (\frac{1}{1^{2}} - \frac{1}{n^{2}}) \Rightarrow n = 4

Now number of spectral lines

N = \frac{n (n - 1)}{2} = \frac{4 (4 - 1)}{2} = 6

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