Question
The wave number of energy emitted when electron jumps from fourth orbit to second orbit in hydrogen in 20497 cm−1. The wave number of energy for the same transition in He+ is
Answer: Option D
:
D
→ν∝z2
→ν2→ν1=[z2z1]2=[21]2=41
→ν2=4→ν1=4×20497=81988cm−1
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:
D
→ν∝z2
→ν2→ν1=[z2z1]2=[21]2=41
→ν2=4→ν1=4×20497=81988cm−1
Was this answer helpful ?
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