Question
Ge and Si diodes conduct at 0.3 V and 0.7 V respectively. In the following figure if Ge diode connection are reversed, the valve of V0 changes by
Answer: Option B
:
B
Consider the case when Ge and Si diodes are connected as show in the given figure.
Equivalent voltage drop across the combination Ge and Si diode = 0.3 V
⇒ Current i=12−0.35kΩ=2.34mA
∴ Out put voltage V0=Ri=5kΩ×2.34mA=11.7V
Now consider the case when diode connection are reversed. In this case voltage drop across the diode's combination = 0.7 V
⇒ current i=12−0.75kΩ=2.26mA
∴V0=iR=2.26mA×5kΩ=11.3V
Hence charge in the value of v0 =11.7 - 11.3=0.4V
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:
B
Consider the case when Ge and Si diodes are connected as show in the given figure.
Equivalent voltage drop across the combination Ge and Si diode = 0.3 V
⇒ Current i=12−0.35kΩ=2.34mA
∴ Out put voltage V0=Ri=5kΩ×2.34mA=11.7V
Now consider the case when diode connection are reversed. In this case voltage drop across the diode's combination = 0.7 V
⇒ current i=12−0.75kΩ=2.26mA
∴V0=iR=2.26mA×5kΩ=11.3V
Hence charge in the value of v0 =11.7 - 11.3=0.4V
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