Question
For the given figures, complete the congruence statements: Â [2 MARKS]
ΔBCA≅ ?               ΔQRS≅ ?
Answer: Option A
:
Each part: 1 Mark
In the given figure,
 In ΔBCA and ΔBTA,
BC = BT (Given)
CA = TAÂ (Given)
BA = BAÂ (Common side)
Thus, ΔBCA≅ΔBTA   [By SSS congruence rule]
In ΔQRS and ΔTPQ,
QT = QSÂ (Given)
PQ = RSÂ (Given)
PT = QRÂ (Given)
Thus, ΔQRS≅ΔTPQ   [By SSS congruence rule]
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:
Each part: 1 Mark
In the given figure,
 In ΔBCA and ΔBTA,
BC = BT (Given)
CA = TAÂ (Given)
BA = BAÂ (Common side)
Thus, ΔBCA≅ΔBTA   [By SSS congruence rule]
In ΔQRS and ΔTPQ,
QT = QSÂ (Given)
PQ = RSÂ (Given)
PT = QRÂ (Given)
Thus, ΔQRS≅ΔTPQ   [By SSS congruence rule]
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