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For one mole of a van der Waal's gas when b =o and T = 300 K, the PV vs 1V plot is shown below.  The value of the Van der Waal's constant "a" (atmL2mol2) is 
For One Mole Of A Van Der Waal's Gas When B =o And T = 300 K...
Options:
A .  1.0
B .  4.5
C .  1.5
D .  3.0
Answer: Option C
:
C
For One Mole Of A Van Der Waal's Gas When B =o And T = 300 K...
P+aV2V=RT
PV + aV = RT
y = RT –a(V)
y = RT –a(x)
So, slope = a = 21.620.132=1.51=1.5

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