Question
For every natural number n, n(n2−1) is divisible by
Answer: Option B
:
B
n(n2−1) = (n - 1)(n)(n + 1)
It is product of three consecutive natural
numbers, so according to Langrange's theorem
it is divisible by 3 ! i.e., 6.
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:
B
n(n2−1) = (n - 1)(n)(n + 1)
It is product of three consecutive natural
numbers, so according to Langrange's theorem
it is divisible by 3 ! i.e., 6.
Was this answer helpful ?
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