Following table shows the points of each player scored in four games: Pl

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Following table shows the points of each player scored in four games:

\begin{matrix} P l a y e r & G a m e & G a m e & G a m e & G a m e 1 & 2 & 3 & 4 S u r a j & 10 & 16 & 14 & 10 A b h i j i t & 8 & 0 & 4 & 6 H a r s h i t h & 13 & D i d n o t & 11 & 8 P l a y \end{matrix}

Based on the above table answer the following questions:
(i) Find the mean to determine Suraj's average number of points scored per game.
(ii) To find the mean number of points per game of Harshith, would you divide the total points by 3 or by 4? Why?
(iii) Abhijit played in all the four games. How would you find the mean?
(iv) Who is the best performer? [4 MARKS]

Answer:
:
Solution: 1 Mark each
(i) Suraj's average number of points.

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{10 + 16 + 14 + 10}{4} = \frac{50}{4}

\Rightarrow M e a n = 12.5

(ii)To find the mean number of points per game of Harshith, mean should be divided by 3 because he played in only 3 games.

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{13 + 11 + 8}{3} = \frac{32}{3}

\Rightarrow M e a n = 10.66

(iii) For Abhijit's game mean is:

M e a n = \frac{S u m o f a l l o b s e r v a t i o n}{T o t a l n u m b e r o f o b s e r v a t i o n}

M e a n = \frac{8 + 0 + 4 + 6}{4} = \frac{18}{4}

\Rightarrow M e a n = 4.5

(iv) Comparing everybody's mean score, Suraj has highest mean.

\Rightarrow

Suraj is best performer.

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