Question
Answer: Option A
:
A
Given,
Resistance values,
R1=R2=R3=3Ω
R4=R5=0.5Ω
Here the resistances R1 and R2 are in series. Let the equivalent resistance of this combination be R12.
R12=R1+R2
R12=3+3=6Ω
NowR12 and R3 are in parallel.
Let the equivalent resistance of thiscombination be R123.
⟹1R123=1R12+1R3
1R123=16+13
R123=2Ω
Now, R4,R123 and R5 are in series.
Let the equivalent resistance of this combination be R.
⟹R=R4+R123+R5
R=0.5+2+0.5Ω
R=3Ω
Using Ohms law,
I=VR
I=3V3Ω=1A
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:
A
Given,
Resistance values,
R1=R2=R3=3Ω
R4=R5=0.5Ω
Here the resistances R1 and R2 are in series. Let the equivalent resistance of this combination be R12.
R12=R1+R2
R12=3+3=6Ω
NowR12 and R3 are in parallel.
Let the equivalent resistance of thiscombination be R123.
⟹1R123=1R12+1R3
1R123=16+13
R123=2Ω
Now, R4,R123 and R5 are in series.
Let the equivalent resistance of this combination be R.
⟹R=R4+R123+R5
R=0.5+2+0.5Ω
R=3Ω
Using Ohms law,
I=VR
I=3V3Ω=1A
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