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Question
Find the zeroes of the polynomial x22.
 
Options:
A .  √2 and −√5
B .  4 and 3
C .  √2 and −√2
D .  −5 and 2 
Answer: Option C
:
C
To find the zeroes, equate the givenpolynomial to zero.
x22=0
Using the identity,a2b2=(a+b)(ab)
(x+2)(x2)=0
x+2=0andx2=0
x=2andx=2
Hence, the zeroes are2,2.

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