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Question
If p(x)=x233x+1, then the value of p(33) is 0.
Options:
A .  True
B .  False
C .  3√y+y2
D .  x
Answer: Option B
:
B
Given,p(x)=x233x+1x=33
p(33)=(33)233(33)+1p(33)=2727+1p(33)=0+1=1
Thus, the given statement is false.

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