Question
Answer:
:
Each part: 1 Mark each
(a) 50∘+x=115∘ (Exterior angle of a triangle is equal to the sum of its interior opposite angles)
x=115∘−50∘
x=65∘
(b)30∘+x=80∘ (Exterior angle of a triangle is equal to the sum of its interior opposite angles)
x=80∘−30∘
x=50∘
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:
Each part: 1 Mark each
(a) 50∘+x=115∘ (Exterior angle of a triangle is equal to the sum of its interior opposite angles)
x=115∘−50∘
x=65∘
(b)30∘+x=80∘ (Exterior angle of a triangle is equal to the sum of its interior opposite angles)
x=80∘−30∘
x=50∘
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