Question
Find the value of the polynomial a3+3a2b+2ab−b2 at a=−2 and b=3. [2 MARKS]
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Steps: 1 Mark
Answer: 1 Mark
The value of the polynomial a3+3a2b+2ab−b2at a = -2 and b = 3
a3+3a2b+2ab−b2
On substituting the values of a and b in the above expression we get:
=(−2)3+3×(−2)2×3+2×(−2)×3−32
=−8+36−12−9=7
So, thevalue of the polynomial a3+3a2b+2ab−b2 at a=−2 and b=3 is 7.
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:
Steps: 1 Mark
Answer: 1 Mark
The value of the polynomial a3+3a2b+2ab−b2at a = -2 and b = 3
a3+3a2b+2ab−b2
On substituting the values of a and b in the above expression we get:
=(−2)3+3×(−2)2×3+2×(−2)×3−32
=−8+36−12−9=7
So, thevalue of the polynomial a3+3a2b+2ab−b2 at a=−2 and b=3 is 7.
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