Question
Add 2a+3b+c+d, −a+b−c−d and 3a−4b−2c−2d. Find the value of the final expression if a=2, b=3, c=4, d=5. [3 MARKS]
Answer:
:
Forming the equation: 1 Mark
Sum: 1 Mark
Value: 1 Mark
We have to find the sum of the expressions
2a+3b+c+d,−a+b−c−d
and 3a−4b−2c−2d.
(2a+3b+c+d)+(−a+b−c−d)+(3a−4b−2c−2d)
2a+3b+c+d−a+b−c−d+3a−4b−2c−2d
2a−a+3a+3b+b−4b+c−c−2c+d−d−2d
4a+0×b−2c−2d
Sum =4a−2c−2d
As per question ,
a = 2, b = 3, c = 4, d = 5
So, on substituting the values we get,
Sum = 4×2−2×4−2×5
=8−8−10
= −10
The value of the expression is −10.
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:
Forming the equation: 1 Mark
Sum: 1 Mark
Value: 1 Mark
We have to find the sum of the expressions
2a+3b+c+d,−a+b−c−d
and 3a−4b−2c−2d.
(2a+3b+c+d)+(−a+b−c−d)+(3a−4b−2c−2d)
2a+3b+c+d−a+b−c−d+3a−4b−2c−2d
2a−a+3a+3b+b−4b+c−c−2c+d−d−2d
4a+0×b−2c−2d
Sum =4a−2c−2d
As per question ,
a = 2, b = 3, c = 4, d = 5
So, on substituting the values we get,
Sum = 4×2−2×4−2×5
=8−8−10
= −10
The value of the expression is −10.
Was this answer helpful ?
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