Question
Find the value of `((243)^(n/3) . 3^(2n + 1))/(9^n xx 3^(n - 1))`
Answer: Option C
Was this answer helpful ?
Sol . `((243)^(n/3) . 3^(2n + 1))/(9^n xx 3^(n - 1))`
= `((3^5)^(n/5) xx 3^(2n + 1))/((3^2)^(n) xx 3^(n - 1))`
= `(3^(5 xx n/5) xx 3^(2n + 1))/(3^(2n) xx 3^(n - 1))`
=`(3^n xx 3^(2n + 1))/(3^(2n) xx 3^(n - 1))`
= ` (3^(n + (2n + 1)))/(3^(2n + n - 1)) `
= `(3^(3n + 1))/(3^(3n - 1))`
= `3^((3n + 1) - (3n - 1)) = 3^2` = 9.
Was this answer helpful ?
More Questions on This Topic :
Question 6.
Evaluate : `(256)^0.16 xx (16)^0....
Question 7.
Evaluate : ` (.00032)^(3/5)`
....
Question 8.
Simplify : `(8/125)^-(4/3)`
....
Question 9.
Simplify : &nbs....
Question 10.
Simplify `(27)^(2/3)`
....
Latest Videos
Latest Test Papers
Submit Solution