Question
If `(1/5)^3y = 0.008`, then find the value of `(0.25)^y.`
Answer: Option D
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Sol. `(1/5)^3y = 0.008` = `8/1000 = 1/125 = (1/5)^3`
`(1/5)^3y = (1/5)^3`
`hArr 3y = 3`
`hArr y = 1.`
`:.` ` (0.25)^y = (0.25)^1 = 0.25`
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