Question
Find the roots of the following equations:
2x+3+2−x=6
2x+3+2−x=6
Answer: Option C
:
C
2x.23+2−x=6
Let2x=z
8z+1z=6
8z2+1=6z
8z2−6z+1=0
8z2−4z−2z+1=0
4z(2z−1)−1(2z−1)=0
(4z−1)(2z−1)=0
z=14,
z=12
2x=14
x=−2
2x=12
x=−1
Roots are x=−2,x=−1
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:
C
2x.23+2−x=6
Let2x=z
8z+1z=6
8z2+1=6z
8z2−6z+1=0
8z2−4z−2z+1=0
4z(2z−1)−1(2z−1)=0
(4z−1)(2z−1)=0
z=14,
z=12
2x=14
x=−2
2x=12
x=−1
Roots are x=−2,x=−1
Was this answer helpful ?
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