Find the general solution of 2sin 3x -1 =0 Options: A . &nbsp x = n π + ( − 1 ) n π 18 B . &nbsp x = n π 3 − ( − 1 ) n π 18 C . &nbsp x = n π + ( − 1 ) n π 6 D . &nbsp x = n π 3 + ( − 1 ) n π 18

Answer: Option D : D 2 s i n 3 x − 1 = 0 s i n 3 x = 1 2 3 x = n π + ( − 1 ) n π 6 x = n π 3 + ( − 1 ) n π 18

Find the general solution of 2sin 3x -1 =0

Question

Find the general solution of 2sin 3x -1 =0

Options:

A .

x = n π + (- 1)^{n} \frac{π}{18}

B .

x = \frac{n π}{3} - (- 1)^{n} \frac{π}{18}

C .

x = n π + (- 1)^{n} \frac{π}{6}

D .

x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}

Answer: Option D
:
D

$2 s i n 3 x - 1 = 0 s i n 3 x = \frac{1}{2} 3 x = n π + (- 1)^{n} \frac{π}{6} x = \frac{n π}{3} + (- 1)^{n} \frac{π}{18}$

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