Question
f(x)={4x−3,x<1x2x≥1, then
limx→1f(x)=
limx→1f(x)=
Answer: Option A
:
A
limx→1−f(x)=limx→1−(4x−3)=1
limx→1+f(x)=limx→1+x2=1
Since LHL = RHL
⇒limx→1f(x)=1
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:
A
limx→1−f(x)=limx→1−(4x−3)=1
limx→1+f(x)=limx→1+x2=1
Since LHL = RHL
⇒limx→1f(x)=1
Was this answer helpful ?
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