Question
Evaluate ∫√1+y2.2ydy
Answer: Option A
:
A
Let I=∫√1+y2.2ydy
Let u=1+y2, then du=2ydy
I=∫u1/2du=u(1/2)+1(1/2)+1Integrate, using rule no. 3 with n=12
= 23u3/2+C
Simpler form= 23(1+y2)3/2+c (Replace u by 1+y2)
Was this answer helpful ?
:
A
Let I=∫√1+y2.2ydy
Let u=1+y2, then du=2ydy
I=∫u1/2du=u(1/2)+1(1/2)+1Integrate, using rule no. 3 with n=12
= 23u3/2+C
Simpler form= 23(1+y2)3/2+c (Replace u by 1+y2)
Was this answer helpful ?
More Questions on This Topic :
Question 1. If y=x5, then dydx=?....
Question 2. If y=x2+5x32+2x, then dydx= ?....
Question 3. ∫π/2−π/2cos xdx....
Question 4. If y=ex find dydx....
Question 5. If f(x)=x cos x, find f"(x), or d2ydx2....
Question 7. Find the derivative of y=sin(x2−4)....
Question 8. If y=e4x sin2x, then dydx=?....
Question 9. Solve the integral I=∫R∞GMmx2dx....
Question 10. If y=x lnx, then dydx=?....
Latest Videos
Latest Test Papers
Submit Solution