Equation of circle touching the line |x-2|+|y-3|=4 will be Options: A . &nbsp(x−2)2+(y−3)2=12 B . &nbsp(x−2)2+(y−3)2=4 C . &nbsp(x−2)2+(y−3)2=10 D . &nbsp(x−2)2+(y−3)2=8

Answer: Option D : D Perpendicular distancefromcentretotangent = radius r = | 2 + 3 − 9 | √ 2 = 4 √ 2 = 4 √ 2 2 = 2 √ 2 Equation of circle is ( x − 2 ) 2 + ( y − 3 ) 2 = 8

Equation of circle touching the line |x-2|+|y-3|=4 will be

Question

Equation of circle touching the line |x-2|+|y-3|=4 will be

Options:

A . (x−2)2+(y−3)2=12

B . (x−2)2+(y−3)2=4

C . (x−2)2+(y−3)2=10

D . (x−2)2+(y−3)2=8

Answer: Option D
:
D
Perpendicular distancefromcentretotangent = radius

Equation of circle touching The Line |x-2|+|y-3|=4 Will B...

r = \frac{| 2 + 3 - 9 |}{\sqrt{2}} = \frac{4}{\sqrt{2}} = \frac{4 \sqrt{2}}{2} = 2 \sqrt{2}

Equation of circle is

(x - 2)^{2} + (y - 3)^{2} = 8

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