The centre of the circle passing through ( 0 , 0 ) and ( 1 , 0 ) and touching the circle x 2 + y 2 = 9 can be Options: A . &nbsp(12,12) B . &nbsp(12,−√2) C . &nbsp(32,12) D . &nbsp(12,32)

Answer: Option B : B Let the centre of the circle be (x, y) x = 0 + 1 2 = 1 2 r = 3 2 √ x 2 + y 2 = 3 2 y = ± √ 2 So there are two circles possible.

The centre of the circle passing through (0,0) and (1,0) and touching the circle

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