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Question
cos248sin212=
 
Options:
A .  √5−14
B .  √5+18
C .  √3−14
D .  √3+12√2
Answer: Option B
:
B
cos2Asin2B= cos(A + B). Cos(A - B)
cos248sin212=cos60.cos36
=12(5+14)=5+18

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