Question
cos248∘−sin212∘=
Answer: Option B
:
B
cos2A−sin2B= cos(A + B). Cos(A - B)
∴cos248∘−sin212∘=cos60∘.cos36∘
=12(√5+14)=√5+18
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:
B
cos2A−sin2B= cos(A + B). Cos(A - B)
∴cos248∘−sin212∘=cos60∘.cos36∘
=12(√5+14)=√5+18
Was this answer helpful ?
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