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Question
The value of sin25+sin210+sin215+..............
+sin285+sin290 is equal to
Options:
A .  7
B .  8
C .  9
D .  192
Answer: Option D
:
D
Given expression is
sin25+sin210+sin215+..............+sin285+sin290.
We know that sin90=1orsin290=1
Similarly, sin45=12 or sin245=12 and the angles are in A.P. of 18 terms. We also know that
sin285=[sin(905)]2=cos25.
Therefore from the complementary rule, we find sin25+sin285=sin25+cos25=1
Therefore,
sin25+sin210+sin215+.............+sin285+sin290
=(1+1+1+1+1+1+1+1)+1+12=912.

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