Question
The value of sin25∘+sin210∘+sin215∘+..............
+sin285∘+sin290∘ is equal to
+sin285∘+sin290∘ is equal to
Answer: Option D
:
D
Given expression is
sin25∘+sin210∘+sin215∘+..............+sin285∘+sin290∘.
We know that sin90∘=1orsin290∘=1
Similarly, sin45∘=1√2 or sin245∘=12 and the angles are in A.P. of 18 terms. We also know that
sin285∘=[sin(90∘−5∘)]2=cos25∘.
Therefore from the complementary rule, we find sin25∘+sin285∘=sin25∘+cos25∘=1
Therefore,
sin25∘+sin210∘+sin215∘+.............+sin285∘+sin290∘
=(1+1+1+1+1+1+1+1)+1+12=912.
Was this answer helpful ?
:
D
Given expression is
sin25∘+sin210∘+sin215∘+..............+sin285∘+sin290∘.
We know that sin90∘=1orsin290∘=1
Similarly, sin45∘=1√2 or sin245∘=12 and the angles are in A.P. of 18 terms. We also know that
sin285∘=[sin(90∘−5∘)]2=cos25∘.
Therefore from the complementary rule, we find sin25∘+sin285∘=sin25∘+cos25∘=1
Therefore,
sin25∘+sin210∘+sin215∘+.............+sin285∘+sin290∘
=(1+1+1+1+1+1+1+1)+1+12=912.
Was this answer helpful ?
More Questions on This Topic :
Question 1. If secθ = 54, then tan θ2 = ....
Question 6. Cot215∘−1cot215∘+1 = ....
Question 7. The minimum value of 3sinθ+4cosθ is ....
Question 8. If 3π4<α<π, then √cosec2α+2cotα is equal to....
Question 10. If cos6α+sin6α+K sin22α=1, then K=....
Submit Solution