Question
Answer: Option A
:
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In the given figure:
In ΔABC and ΔPQR
AB = PR (Given)
BC = PQ (Given)
AC = QR (Given)
Therefore, ΔABC≅ΔPQR by SSS condition.
Therefore,
∠A=∠R=50∘;
∠B=∠P;
∠C=∠Q=60∘.
Using angle sum property in Δ ABC,
∠A+∠B+∠C=180∘
⇒ 50∘+∠B+60∘=180∘
⇒ ∠B=70∘
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