Question
Calculate Molarity of a solution having 3.42 gm sucrose in 500 mL - solution.
Answer: Option B
:
B
We know that,
Molarity=No. of moles of soluteNo of litres of solution
We know the given weight of sucrose from which the number of moles of sucrose can be calculated. Therefore No. of moles =GivenweightMolecularweight(solute is sucrose)
=3.42342=0.01
When 0.01 moles of sucrose is added to 500ml
⇒Molarity=0.01×1500×10−3(1mL=10−3L)
⇒ Molarity = 0.02 M
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:
B
We know that,
Molarity=No. of moles of soluteNo of litres of solution
We know the given weight of sucrose from which the number of moles of sucrose can be calculated. Therefore No. of moles =GivenweightMolecularweight(solute is sucrose)
=3.42342=0.01
When 0.01 moles of sucrose is added to 500ml
⇒Molarity=0.01×1500×10−3(1mL=10−3L)
⇒ Molarity = 0.02 M
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