Question
How many carbon atoms are present in 0.35 mol of C6H12O6 :
Answer: Option B
:
B
∴1moleofC6H12O6has=6NAatomsofC∴0.35moleofC6H12O6has=6×0.35NAatomsofC=2.1NAatoms
=2.1×6.022×1023=1.26×1024 carbon atoms
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:
B
∴1moleofC6H12O6has=6NAatomsofC∴0.35moleofC6H12O6has=6×0.35NAatomsofC=2.1NAatoms
=2.1×6.022×1023=1.26×1024 carbon atoms
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