Question
Brakes are applied to a truck to produce an acceleration of –10 ms−2. If the truck takes 5 s to stop after applying the brakes, then find the distance covered by the truck before coming to rest.
Answer: Option B
:
B
Given, final velocity, v=0, acceleration,a=−10ms−2, time taken, t=5s.
Let the initial velocity be u.
From the first equation of motion, v=u+at,
0=u+(−10×5)
⇒u=50ms−1
From third equation of motion,v2 = u2+2as,
0=502+2×−10×s
⇒s=125m
Therefore, the truck will stop after 125m.
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:
B
Given, final velocity, v=0, acceleration,a=−10ms−2, time taken, t=5s.
Let the initial velocity be u.
From the first equation of motion, v=u+at,
0=u+(−10×5)
⇒u=50ms−1
From third equation of motion,v2 = u2+2as,
0=502+2×−10×s
⇒s=125m
Therefore, the truck will stop after 125m.
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