Question
If a body is thrown up with an initial velocity u and covers a maximum height of h, then h is equal to u22g.
Answer: Option A
:
A
Let theinitial velocity be u, final velocity be v, acceleration be aand distance covered be s.
Using the equation ,v2 = u2+2as,
Here a=−g
[∵ acceleration due to gravity is acting opposite to the direction of motion]
s=h
At the highest point, v=0
∴0=u2−2gh
⇒h=u22g
Was this answer helpful ?
:
A
Let theinitial velocity be u, final velocity be v, acceleration be aand distance covered be s.
Using the equation ,v2 = u2+2as,
Here a=−g
[∵ acceleration due to gravity is acting opposite to the direction of motion]
s=h
At the highest point, v=0
∴0=u2−2gh
⇒h=u22g
Was this answer helpful ?
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