Question
Assume that the total surface area of a human body is 1.6 m2 and that it radiates like an ideal radiator. Calculate the amount of energy radiated per second by the body if the body temperature is 37∘ C.Stefan constant σ is 6.0×10−8W/m2−K4.
Answer: Option B
:
B
Stefan's law: ΔQΔt=eσAT4
For an ideal radiator e = 1 ⇒ΔQΔt=6×10−8×1.6×(273+37)4
=6×10−8×1.6×314×104
= 887 J per second.
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:
B
Stefan's law: ΔQΔt=eσAT4
For an ideal radiator e = 1 ⇒ΔQΔt=6×10−8×1.6×(273+37)4
=6×10−8×1.6×314×104
= 887 J per second.
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