Question
- After working for 6 days, Ashok finds that only 1/3rd of the work has been done. He employs Ravi who is 60% as efficient as Ashok. How many days more would Ravi take to complete the work?
Answer: Option B
To solve this problem, we first need to calculate Ashok's efficiency in terms of work done per day. If Ashok worked for 6 days and only 1/3rd of the work has been done, then his efficiency can be calculated as follows:
Work done by Ashok in 6 days = 1/3 of the total workWork done by Ashok per day = 1/3 of the total work ÷ 6 days = 1/18 of the total work
Next, we need to calculate Ravi's efficiency in terms of work done per day. Ravi is 60% as efficient as Ashok, so his efficiency can be calculated as follows:
Work done by Ravi per day = 60% of Ashok's efficiency = 60% of 1/18 of the total work
Finally, we need to calculate the number of days Ravi would take to complete the remaining 2/3rd of the work. We can use the formula:
Time taken by Ravi to complete the work = Remaining work ÷ Ravi's efficiency per day
Substituting the values, we get:
Time taken by Ravi to complete the work = 2/3 of the total work ÷ (60% of 1/18 of the total work) = 20 days
Here is a summary of the key points in bullet form:
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To solve this problem, we first need to calculate Ashok's efficiency in terms of work done per day. If Ashok worked for 6 days and only 1/3rd of the work has been done, then his efficiency can be calculated as follows:
Work done by Ashok in 6 days = 1/3 of the total workWork done by Ashok per day = 1/3 of the total work ÷ 6 days = 1/18 of the total work
Next, we need to calculate Ravi's efficiency in terms of work done per day. Ravi is 60% as efficient as Ashok, so his efficiency can be calculated as follows:
Work done by Ravi per day = 60% of Ashok's efficiency = 60% of 1/18 of the total work
Finally, we need to calculate the number of days Ravi would take to complete the remaining 2/3rd of the work. We can use the formula:
Time taken by Ravi to complete the work = Remaining work ÷ Ravi's efficiency per day
Substituting the values, we get:
Time taken by Ravi to complete the work = 2/3 of the total work ÷ (60% of 1/18 of the total work) = 20 days
Here is a summary of the key points in bullet form:
- Ashok worked for 6 days and only 1/3rd of the work has been done, so his efficiency per day can be calculated as 1/18 of the total work.
- Ravi is 60% as efficient as Ashok, so his efficiency per day can be calculated as 60% of 1/18 of the total work.
- The time taken by Ravi to complete the remaining 2/3rd of the work can be calculated using the formula: Remaining work ÷ Ravi's efficiency per day = 20 days.
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Now, Ravi is 60% effecient than Ashok. i.e 60/100*1/3 = 1/5.
Hence, Ravi complete the 1/5th of work in 6 days as he is 60% effecient than Ashok.
Remaining work = 1-1/3
i.e 2/3 or 0.67.
Ravi complete 1/5th of work in 6 days i.e 0.2 of total work in 6 days.
In 1 days Ravi can do 0.033 of total work.
Remaining time = 0.67/0.033 i.e 20 days