Question
A train can travel 50% faster than a car. Both start from point A at the same time and reach point B 75 kms away from A at the same time. On the way, however, the train lost about 12.5 minutes while stopping at the stations. The speed of the car is:
Answer: Option C
Was this answer helpful ?
Let speed of the car be x kmph.
Then, speed of the train = \(\frac{150}{100}x = \left(\frac{3}{2}x\right)kmph.\)
\(\therefore \frac{75}{x}-\frac{75}{(\frac{3}{2})x}=\frac{125}{10\times60}\)
\(\frac{75}{x}-\frac{50}{x}=\frac{5}{24}\)
\(x=\left(\frac{25\times24}{5}\right)= 120kmph.\)
Was this answer helpful ?
More Questions on This Topic :
Latest Videos
Latest Test Papers
Submit Solution