Question
A train 100 meter long meets a man going in opposite direction at 5 km/h and passes him in 71/5 seconds. What is the speed of the train (in km/hr)?
Answer: Option A
$$\eqalign{
& {\text{Relative speed of man & train}} \cr
& {\text{ = }}\frac{{100 \times 5}}{{36}} \times \frac{{18}}{5} \cr
& {\text{ = 50km/hr}} \cr
& \therefore {\text{speed of train}} \cr
& {\text{ = 50}} - {\text{5}} \cr
& {\text{ = 45 km/hr}} \cr} $$
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$$\eqalign{
& {\text{Relative speed of man & train}} \cr
& {\text{ = }}\frac{{100 \times 5}}{{36}} \times \frac{{18}}{5} \cr
& {\text{ = 50km/hr}} \cr
& \therefore {\text{speed of train}} \cr
& {\text{ = 50}} - {\text{5}} \cr
& {\text{ = 45 km/hr}} \cr} $$
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