A tower stands vertically on the ground. From a point on the ground, which is 2

Question

A tower stands vertically on the ground. From a point on the ground, which is 24 m away from the foot of the tower, the angle of elevation of the top of the tower is found to be

60^{\circ}

. Find the height of the tower.

Options:

A . 26√3 m

B . 24√3 m

C . 24 m

D . 26 m

Answer: Option B
:
B

A Tower Stands Vertically On The Ground. From A Point On The...

The above

Δ A B C

represents the given situation.
AB = 24 m
In Triangle ABC,

t a n 60^{\circ} = \sqrt{3} = \frac{C B}{A B} \Rightarrow A B \times \sqrt{3} = C B \Rightarrow C B = 24 \sqrt{3} m .

Hence, the height of the tower =

24 \sqrt{3} m .

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