Question
A ray of light is incident at the glass–water interface at an angle i, it emerges finally parallel to the surface of water, then the value of μg would be
Answer: Option B
:
B
For glass water interface gμω=sinisinr.....(i)and For water-air interface ωμa=sinrsin90......(ii)
∴gμωxωμa=sini⇒μg=1sini
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B
For glass water interface gμω=sinisinr.....(i)and For water-air interface ωμa=sinrsin90......(ii)
∴gμωxωμa=sini⇒μg=1sini
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