Question
A random variable X has the following probability distribution
XP(X=x)XP(X=x)0λ511λ13λ613λ25λ715λ37λ817λ49λ
then, λ is equal to
XP(X=x)XP(X=x)0λ511λ13λ613λ25λ715λ37λ817λ49λ
then, λ is equal to
Answer: Option A
:
A
∑8x=0P(X)=1⇒P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)=1=λ+3λ+5λ+7λ+9λ+11λ+13λ+15λ+17λ=1⇒92(λ+17λ)=1⇒81λ=1∴λ=181
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:
A
∑8x=0P(X)=1⇒P(0)+P(1)+P(2)+P(3)+P(4)+P(5)+P(6)+P(7)+P(8)=1=λ+3λ+5λ+7λ+9λ+11λ+13λ+15λ+17λ=1⇒92(λ+17λ)=1⇒81λ=1∴λ=181
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