Answer: Option C
:
C
The metal sheet is in the shape of a cuboid.
Total surface area of the cuboid is given by2 (lb + bh + hl) = 2[(27 ×8) + (8 ×1) + (1 ×27)] = 502 $c{m}^2$.
When themetal sheet is melted into a cube, then the volume of themetal sheet will be equal to the volume of thecube.
Hence, Volume of the cuboid = Volume of the cube
Let eachside of thecube be $a$
Hence, 27 × 8 × 1 = $a^3$
⇒$a$ = 6 cm
Total Surface area of the cube is given by$6a^2$ = 6 × (6)² = 216 $c{m}^2$.
Hence, the difference between surface areas of two solids = (502 -216)$c{m}^2$ = 286 $c{m}^2$.