Question
The age of a man is three times the sum of the ages of his two sons. Five years hence, his age will be double of the sum of the ages of his sons. The father's present age is:
Answer: Option C
- Let the sum of present ages of the two sons be X years
Then, father’s present age = 3X years
(3X + 5) = 2 (X +10) 3X + 5 = 2X + 20 X = 15
Hence, father's present age = 45 years
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- Let the sum of present ages of the two sons be X years
Then, father’s present age = 3X years
(3X + 5) = 2 (X +10) 3X + 5 = 2X + 20 X = 15
Hence, father's present age = 45 years
Was this answer helpful ?
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